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number-of-boomerangs

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Number of Boomerangs – LeetCode 447

Problem

Description

Given n points in the plane that are all pairwise distinct, a “boomerang” is a tuple of points (i, j, k) such that the distance between i and j equals the distance between i and k (the order of the tuple matters).

Find the number of boomerangs. You may assume that n will be at most 500 and coordinates of points are all in the range [-10000, 10000] (inclusive).

Example

Input:
[[0,0],[1,0],[2,0]]

Output:
2

Explanation:
The two boomerangs are [[1,0],[0,0],[2,0]] and [[1,0],[2,0],[0,0]]

Answer

Original

Code

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class Solution {
public:
    int numberOfBoomerangs(vector<pair<int, int>>& points) {
        int res = 0;
        for (int i = 0; i < points.size(); ++i) {
            unordered_map<int, int> m;
            for (int j = 0; j < points.size(); ++j) {
                int a = points[i].first - points[j].first;
                int b = points[i].second - points[j].second;
                ++m[a * a + b * b];
            }
            for (auto it = m.begin(); it != m.end(); ++it) {
                res += it->second * (it->second - 1);
            }
        }
        return res;
    }
};

思路

数学题。时间复杂度$O(n^2)$，空间复杂度$O(1)$。
耗时$282$ ms，排名$33.13\%$

Better

思路

还没看到更好的思路。